What is the rotating speed of a three-phase 30 Hz 6-pole motor?

Prepare for the NEIEP Electrical Theory and Application (430) Exam. Leverage interactive flashcards and engaging multiple-choice questions, each with hints and comprehensive explanations. Get ready to excel!

Multiple Choice

What is the rotating speed of a three-phase 30 Hz 6-pole motor?

Explanation:
Rotating speed in a polyphase motor is set by the synchronous speed, which is determined by the frequency and the number of poles. The formula is Ns = 120 f / P. With a 30 Hz supply and 6 poles, the calculation is 120 × 30 / 6 = 600 rpm. This is the speed at which the stator’s magnetic field rotates. In an induction motor, the rotor typically runs a bit slower than synchronous speed due to slip, so the actual shaft speed under load would be slightly less than 600 rpm. The same formula explains other common cases: for example, 30 Hz with 4 poles would give 900 rpm, and other combinations shift the speed accordingly.

Rotating speed in a polyphase motor is set by the synchronous speed, which is determined by the frequency and the number of poles. The formula is Ns = 120 f / P. With a 30 Hz supply and 6 poles, the calculation is 120 × 30 / 6 = 600 rpm. This is the speed at which the stator’s magnetic field rotates. In an induction motor, the rotor typically runs a bit slower than synchronous speed due to slip, so the actual shaft speed under load would be slightly less than 600 rpm. The same formula explains other common cases: for example, 30 Hz with 4 poles would give 900 rpm, and other combinations shift the speed accordingly.

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